Master Trigonometric Identities: Solve 5 Challenging Word Problems with Step-by-Step Answers

5 1 word problem practice trigonometric identities answers

If you are struggling with solving word problems involving trigonometric identities, you’ve come to the right place. This article provides practice problems along with the answers for a better understanding of the topic.

Trigonometric identities are mathematical equations involving trigonometric functions such as sine, cosine, and tangent. These identities are fundamental in solving various real-world problems that involve angles and distances. However, applying these identities to word problems can sometimes be challenging.

In this article, we have compiled five word problem practice questions to help you strengthen your skills in using trigonometric identities. Each problem is carefully crafted to test your understanding and problem-solving abilities. After you attempt each problem, you can find the answer provided below for self-assessment.

By practicing these word problems, you will not only gain confidence in using trigonometric identities but also develop a deeper understanding of their applications in real-life situations. So let’s dive into the practice problems and enhance your skills in solving word problems involving trigonometric identities!

1 Word Problem Practice Trigonometric Identities Answers

1 Word Problem Practice Trigonometric Identities Answers

Trigonometric identities are crucial in solving various mathematical problems involving angles and triangles. They allow us to manipulate and simplify trigonometric expressions, making them easier to solve. However, applying these identities correctly can be challenging for students. In order to enhance their understanding and improve their skills, practicing word problems can be beneficial.

Word problems provide real-life scenarios where trigonometric identities can be applied. By solving these problems, students can develop a deeper understanding of how to use identities effectively. Here are some answers to one-word problem that can help illustrate the application of trigonometric identities:

  • Problem: A flagpole is located at the top of a hill. From a point 120 feet downhill, the angle of elevation to the top of the flagpole is 35 degrees. Find the height of the flagpole.
  • Solution: Let’s assume the height of the flagpole is represented by the variable ‘h’. From the problem, we know that the distance between the point and the flagpole is 120 feet. Using the tangent function, we can set up the equation: tan(35 degrees) = h/120. Solving for h, we have h = 120 * tan(35 degrees). Evaluating this expression gives us the height of the flagpole.

By practicing word problems like this, students can become more familiar with the application of trigonometric identities and gain confidence in solving similar problems. It’s important to not only memorize the identities but to also understand how and when to use them in different contexts. Regular practice and exposure to word problems can help strengthen these skills.

Section 1: What are Trigonometric Identities?

Trigonometric identities are mathematical equations that relate various trigonometric functions to each other. These identities are derived from the properties of triangles and angles in the unit circle. Trigonometric identities are essential tools in solving trigonometric equations, simplifying trigonometric expressions, and proving other mathematical theorems.

Trigonometric identities come in various forms, including reciprocal identities, quotient identities, Pythagorean identities, and co-function identities. These identities help establish relationships between the trigonometric functions such as sine, cosine, tangent, cosecant, secant, and cotangent.

Reciprocal identities relate the reciprocal of a trigonometric function to another trigonometric function. For example, the reciprocal identity for sine states that the cosecant of an angle is equal to one divided by the sine of that angle.

Quotient identities express the ratio of two trigonometric functions in terms of one another. An example of a quotient identity is the tangent identity, which states that the tangent of an angle is equal to the sine of that angle divided by the cosine of that angle.

Pythagorean identities are based on the Pythagorean theorem and establish relationships between the trigonometric functions squared. The most well-known Pythagorean identity is the sine squared identity, which states that the square of the sine of an angle plus the square of the cosine of that angle is equal to one.

Co-function identities relate the trigonometric functions of complementary angles. For example, the co-function identity for sine states that the sine of an angle is equal to the cosine of the complementary angle. These identities are useful in simplifying trigonometric expressions and solving equations.

In summary, trigonometric identities are fundamental equations that establish relationships between trigonometric functions. They play a crucial role in various areas of mathematics and are widely used in trigonometry, calculus, physics, and engineering.

Section 2: Practice Problems to Improve Understanding

In order to fully grasp the concepts of trigonometric identities, it is essential to practice solving problems that require their application. This section provides a series of practice problems that will help improve your understanding of these identities.

Problem 1:

Given that sin(x) = 3/5 and cos(x) = 4/5, find the value of tan(x).

Solution:

To find the value of tan(x), we can use the identity tan(x) = sin(x) / cos(x). Substituting the given values, we have:

tan(x) = (3/5) / (4/5) = 3/4.

Problem 2:

Simplify the expression sin^2(x) – cos^2(x).

Solution:

We can use the identity sin^2(x) – cos^2(x) = 1 – cos^2(x) – cos^2(x) = 1 – 2cos^2(x). This simplifies the expression to 1 – 2cos^2(x).

Problem 3:

Given that cos(2x) = -1/3, find sin(2x).

Solution:

We can use the trigonometric identity cos(2x) = 1 – 2sin^2(x) to find sin(2x). Substituting the given value, we have:

-1/3 = 1 – 2sin^2(x),

2sin^2(x) = 1 + 1/3,

sin^2(x) = 2/3,

sin(x) = ±√(2/3).

Problem 4:

Simplify the expression sin(x) / sec(x) * csc(x).

Solution:

We can rewrite the expression as (sin(x) * csc(x)) / sec(x). Using the identity csc(x) = 1 / sin(x) and sec(x) = 1 / cos(x), we have:

(sin(x) * csc(x)) / sec(x) = (sin(x) * 1/sin(x)) / (1 / cos(x)) = cos(x).

By practicing these and similar problems, you will gain confidence in applying trigonometric identities to solve various trigonometry problems. Remember to always draw upon the identities you have learned and use them as tools to simplify and solve equations or expressions.

Section 3: Problem 1 Answer and Explanation

Section 3: Problem 1 Answer and Explanation

To solve this equation, we can rewrite sin(x) – cos(x) = 0 as sin(x) = cos(x). We know that sin(x) / cos(x) = tan(x), so we can write the equation as tan(x) = 1.

We know that the solutions to the equation tan(x) = 1 are x = π/4 + kπ, where k is an integer. Since we are looking for solutions in the interval [0, 2π], we need to find the values of k that satisfy this condition.

We can start by setting k = 0 and finding the first solution in the interval [0, 2π]. Plugging in k = 0, we get x = π/4. This satisfies the equation since tan(π/4) = 1.

Now, we need to find the next solution in the interval [0, 2π]. We can set k = 1 and plug it into the equation to find x. Plugging in k = 1, we get x = 5π/4. This also satisfies the equation since tan(5π/4) = 1.

Therefore, the solutions to the equation sin(x) – cos(x) = 0 in the interval [0, 2π] are x = π/4 and x = 5π/4.

Section 4: Problem 2 Answer and Explanation

Let’s begin by stating the problem:

Problem: Simplify the expression sin(x) – tan(x) + cos(x).

To simplify this expression, we need to use trigonometric identities to rewrite each term in a way that allows us to combine them. Let’s break it down:

  • Sin(x): This term represents the sine of angle x. We can rewrite this using the Pythagorean identity: sin^2(x) + cos^2(x) = 1. Rearranging, we have sin(x) = sqrt(1 – cos^2(x)).
  • Tan(x): This term represents the tangent of angle x. We know that tan(x) = sin(x)/cos(x). Using the identity from above, we can rewrite this as tan(x) = sqrt(1 – cos^2(x))/cos(x).
  • Cos(x): This term represents the cosine of angle x. No further simplification is needed for this term, as it cannot be combined with the other terms.

Now let’s substitute these simplified expressions back into the original expression:

Simplified expression: sqrt(1 – cos^2(x)) – sqrt(1 – cos^2(x))/cos(x) + cos(x)

We can combine the terms with a common denominator of cos(x):

Simplified expression: sqrt(1 – cos^2(x)) – sqrt(1 – cos^2(x))/cos(x) + cos^2(x)/cos(x)

Next, let’s simplify the expression by multiplying through by cos(x) to eliminate the denominators:

Simplified expression: cos(x)*sqrt(1 – cos^2(x)) – sqrt(1 – cos^2(x)) + cos^2(x)

Finally, we can combine like terms:

Simplified expression: cos(x)*sqrt(1 – cos^2(x)) – sqrt(1 – cos^2(x)) + cos^2(x)

This is the simplified form of the expression sin(x) – tan(x) + cos(x).

Section 5: Problem 3 Answer and Explanation

In this problem, we are given a trigonometric expression and we need to simplify it using trigonometric identities. The given expression is:

tan^2(x) – sin^2(x)

To simplify this expression, we can start by using the identity tan^2(x) = sec^2(x) – 1. By substituting this identity into the given expression, we get:

sec^2(x) – 1 – sin^2(x)

Next, we can use the identity sec^2(x) = 1 + tan^2(x). Substituting this identity into the expression, we now have:

1 + tan^2(x) – 1 – sin^2(x)

Simplifying further, the 1 and the -1 cancel out, leaving us with:

tan^2(x) – sin^2(x)

Finally, we can recognize that this expression is equal to the identity 1 – cos^2(x). Substituting this identity into the expression, we get:

1 – cos^2(x)

Therefore, the simplified form of the given expression is 1 – cos^2(x).

Section 6: Problem 4 Answer and Explanation

Section 6: Problem 4 Answer and Explanation

In problem 4, we are given the equation:

cos(θ) – sin(θ) = -1

To solve this equation, we can start by rearranging it to separate the cosine and sine terms:

cos(θ) = sin(θ) – 1

Now, we can square both sides of the equation to eliminate the square root:

cos(θ)^2 = (sin(θ) – 1)^2

Expanding the right side of the equation, we get:

cos(θ)^2 = sin(θ)^2 – 2sin(θ) + 1

Since we know that cos(θ)^2 + sin(θ)^2 = 1 (from the Pythagorean identity), we can substitute this in the equation:

1 – sin(θ)^2 = sin(θ)^2 – 2sin(θ) + 1

Simplifying further, we get:

2sin(θ)^2 – 2sin(θ) = 0

Factoring out a common factor of 2sin(θ), we get:

2sin(θ)(sin(θ) – 1) = 0

So, we have two possible solutions:

  1. sin(θ) = 0
  2. sin(θ) – 1 = 0 (which simplifies to sin(θ) = 1)

From the first equation, we know that θ can be any multiple of π, so the solutions are:

θ = nπ, where n is an integer

From the second equation, we know that sin(θ) = 1 only when θ = π/2, so the solution is:

θ = π/2

Therefore, the solutions for problem 4 are:

θ = nπ, where n is an integer, and θ = π/2

Section 7: Problem 5 Answer and Explanation

In problem 5, we are given a trigonometric equation involving the sine and cosine functions. The equation is:

sin(x) – cos(x) = 1

To solve this equation, we can start by rearranging it to isolate either the sine or cosine function. Let’s choose to isolate the cosine function. We can do this by subtracting the sine function from both sides:

sin(x) – cos(x) – sin(x) = 1 – sin(x)

Simplifying the left side of the equation, we have:

-cos(x) = 1 – sin(x)

Next, we can square both sides of the equation to eliminate the absolute values. This will give us:

cos^2(x) = (1 – sin(x))^2

Expanding the right side of the equation, we have:

cos^2(x) = 1 – 2sin(x) + sin^2(x)

Using the Pythagorean identity sin^2(x) + cos^2(x) = 1, we can substitute cos^2(x) with 1 – sin^2(x):

1 – sin^2(x) = 1 – 2sin(x) + sin^2(x)

Simplifying this equation further, we have:

2sin^2(x) – 2sin(x) = 0

Now, we can factor out sin(x) from the equation:

sin(x)(2sin(x) – 2) = 0

Setting each factor equal to zero, we have two possible solutions:

  • sin(x) = 0
  • 2sin(x) – 2 = 0

Solving for x in the first equation, we find that x can be any multiple of π (Pi), since sin(x) = 0 when x is a multiple of π.

In the second equation, we can solve for sin(x) by adding 2 to both sides and then dividing by 2:

2sin(x) – 2 + 2 = 0 + 2

2sin(x) = 2

sin(x) = 1

We know that sin(x) = 1 when x is equal to π/2, so this gives us another possible solution.

Therefore, the solutions to the equation sin(x) – cos(x) = 1 are x = nπ and x = π/2, where n is an integer.